(2n+(1/n^2))^6

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Solution for (2n+(1/n^2))^6 equation:


D( n )

n^2 = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

(2*n+1/(n^2))^6 = 0

(2*n+n^-2)^6 = 0

2*n+n^-2 = 0

n*(n^-3+2) = 0

1*n^-3 = -2 // : 1

n^-3 = -2

-3 < 0

1/(n^3) = -2 // * n^3

1 = -2*n^3 // : -2

-1/2 = n^3

n^3 = -1/2 // ^ 1/3

n = -(1/2)^(1/3)

n*(n+(1/2)^(1/3)) = 0

n^6*(n+(1/2)^(1/3))^6 = 0

( n+(1/2)^(1/3) )

n+(1/2)^(1/3) = 0 // - (1/2)^(1/3)

n = -(1/2)^(1/3)

( n )

n = 0

n in { 0}

n in { -(1/2)^(1/3), -(1/2)^(1/3), -(1/2)^(1/3), -(1/2)^(1/3), -(1/2)^(1/3), -(1/2)^(1/3) }

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